The figure, not drawn to scale, is made of two connected cubical tanks, N and P. Tank N is sealed at the top and completely filled to the brim. Tank P is ³₄ filled with 136629 mℓ of water. The height of the water level in Tank P is 3 cm higher than that in Tank N. Height of Tank P is 64 cm. Water is then drained from the container and the height of the water level from the base falls to 28 cm.

1. What is the capacity of Tank P in litres?
2. What is the volume of water in the tank now in litres?

(a)
³₄ of Tank P = 136629 mℓ
¹₄ of Tank P = 136629 ÷ 3 = 45543 mℓ
⁴₄ of Tank P = 45543 x 4 = 182172 mℓ

1 ℓ = 1000 mℓ

Capacity of Tank P = 182172 mℓ = 182.172 ℓ

(b)
Fraction of Tank P not filled
= 1 - ³₄
= ¹₄

Height of Tank P not filled
= ¹₄ x 64 cm
= 16 cm

Height of Tank N
= 64 - 16 - 3
= 45 cm

Volume of remaining water in Tank N
= 45 x 45 x 28
= 56700 cm³ 

Volume of remaining water in Tank P
= 64 x 64 x 28
= 114688 cm³ 

Total volume of remaining water in the tank
= 56700 + 114688
= 171388 cm³

1 ℓ = 1000 cm³
171388 cm³ = 171.388 ℓ

Answer(s): (a) 182.172 ℓ; (b) 171.388 ℓ