The figure, not drawn to scale, is made of two connected cubical containers, F and G. Container F is sealed at the top and completely filled to the brim. Container G is
35 filled with 194391 mℓ of water. The height of the water level in Container G is 1 cm higher than that in Container F. Height of Container G is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 37 cm.
- What is the capacity of Container G in litres?
- What is the volume of water in the container now in litres?
(a)
35 of Container G = 194391 mℓ
15 of Container G = 194391 ÷ 3 = 64797 mℓ
55 of Container G = 64797 x 5 = 323985 mℓ
1 ℓ = 1000 mℓ
Capacity of Container G = 323985 mℓ = 323.985 ℓ
(b)
Fraction of Container G not filled
= 1 -
35 =
25 Height of Container G not filled
=
25 x 70 cm
= 28 cm
Height of Container F
= 70 - 28 - 1
= 41 cm
Volume of remaining water in Container F
= 41 x 41 x 37
= 62197 cm
3 Volume of remaining water in Container G
= 70 x 70 x 37
= 181300 cm
3 Total volume of remaining water in the container
= 62197 + 181300
= 243497 cm
3
1 ℓ = 1000 cm
3 243497 cm
3 = 243.497 ℓ
Answer(s): (a) 323.985 ℓ; (b) 243.497 ℓ