The figure, not drawn to scale, is made of two connected cubical tanks, E and F. Tank E is sealed at the top and completely filled to the brim. Tank F is ⁴₅ filled with 130576 mℓ of water. The height of the water level in Tank F is 2 cm higher than that in Tank E. Height of Tank F is 60 cm. Water is then drained from the container and the height of the water level from the base falls to 22 cm.

1. What is the capacity of Tank F in litres?
2. What is the volume of water in the tank now in litres?

(a)
⁴₅ of Tank F = 130576 mℓ
¹₅ of Tank F = 130576 ÷ 4 = 32644 mℓ
⁵₅ of Tank F = 32644 x 5 = 163220 mℓ

1 ℓ = 1000 mℓ

Capacity of Tank F = 163220 mℓ = 163.22 ℓ

(b)
Fraction of Tank F not filled
= 1 - ⁴₅
= ¹₅

Height of Tank F not filled
= ¹₅ x 60 cm
= 12 cm

Height of Tank E
= 60 - 12 - 2
= 46 cm

Volume of remaining water in Tank E
= 46 x 46 x 22
= 46552 cm³ 

Volume of remaining water in Tank F
= 60 x 60 x 22
= 79200 cm³ 

Total volume of remaining water in the tank
= 46552 + 79200
= 125752 cm³

1 ℓ = 1000 cm³
125752 cm³ = 125.752 ℓ

Answer(s): (a) 163.22 ℓ; (b) 125.752 ℓ