The figure, not drawn to scale, is made of two connected cubical containers, L and M. Container L is sealed at the top and completely filled to the brim. Container M is ³₅ filled with 113805 mℓ of water. The height of the water level in Container M is 5 cm higher than that in Container L. Height of Container M is 63 cm. Water is then drained from the container and the height of the water level from the base falls to 25 cm.

1. What is the capacity of Container M in litres?
2. What is the volume of water in the container now in litres?

(a)
³₅ of Container M = 113805 mℓ
¹₅ of Container M = 113805 ÷ 3 = 37935 mℓ
⁵₅ of Container M = 37935 x 5 = 189675 mℓ

1 ℓ = 1000 mℓ

Capacity of Container M = 189675 mℓ = 189.675 ℓ

(b)
Fraction of Container M not filled
= 1 - ³₅
= ²₅

Height of Container M not filled
= ²₅ x 63 cm
= 25.2 cm

Height of Container L
= 63 - 25.2 - 5
= 32.8 cm

Volume of remaining water in Container L
= 32.8 x 32.8 x 25
= 26896 cm³ 

Volume of remaining water in Container M
= 63 x 63 x 25
= 99225 cm³ 

Total volume of remaining water in the container
= 26896 + 99225
= 126121 cm³

1 ℓ = 1000 cm³
126121 cm³ = 126.121 ℓ

Answer(s): (a) 189.675 ℓ; (b) 126.121 ℓ