The figure, not drawn to scale, is made of two connected cubical tanks, M and N. Tank M is sealed at the top and completely filled to the brim. Tank N is
35 filled with 168948 mℓ of water. The height of the water level in Tank N is 1 cm higher than that in Tank M. Height of Tank N is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 20 cm.
- What is the capacity of Tank N in litres?
- What is the volume of water in the tank now in litres?
(a)
35 of Tank N = 168948 mℓ
15 of Tank N = 168948 ÷ 3 = 56316 mℓ
55 of Tank N = 56316 x 5 = 281580 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank N = 281580 mℓ = 281.58 ℓ
(b)
Fraction of Tank N not filled
= 1 -
35 =
25 Height of Tank N not filled
=
25 x 70 cm
= 28 cm
Height of Tank M
= 70 - 28 - 1
= 41 cm
Volume of remaining water in Tank M
= 41 x 41 x 20
= 33620 cm
3 Volume of remaining water in Tank N
= 70 x 70 x 20
= 98000 cm
3 Total volume of remaining water in the tank
= 33620 + 98000
= 131620 cm
3
1 ℓ = 1000 cm
3 131620 cm
3 = 131.62 ℓ
Answer(s): (a) 281.58 ℓ; (b) 131.62 ℓ