The figure, not drawn to scale, is made of two connected cubical containers, D and E. Container D is sealed at the top and completely filled to the brim. Container E is ²₅ filled with 132996 mℓ of water. The height of the water level in Container E is 2 cm higher than that in Container D. Height of Container E is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 25 cm.

1. What is the capacity of Container E in litres?
2. What is the volume of water in the container now in litres?

(a)
²₅ of Container E = 132996 mℓ
¹₅ of Container E = 132996 ÷ 2 = 66498 mℓ
⁵₅ of Container E = 66498 x 5 = 332490 mℓ

1 ℓ = 1000 mℓ

Capacity of Container E = 332490 mℓ = 332.49 ℓ

(b)
Fraction of Container E not filled
= 1 - ²₅
= ³₅

Height of Container E not filled
= ³₅ x 70 cm
= 42 cm

Height of Container D
= 70 - 42 - 2
= 26 cm

Volume of remaining water in Container D
= 26 x 26 x 25
= 16900 cm³ 

Volume of remaining water in Container E
= 70 x 70 x 25
= 122500 cm³ 

Total volume of remaining water in the container
= 16900 + 122500
= 139400 cm³

1 ℓ = 1000 cm³
139400 cm³ = 139.4 ℓ

Answer(s): (a) 332.49 ℓ; (b) 139.4 ℓ