The figure, not drawn to scale, is made of two connected cubical tanks, R and S. Tank R is sealed at the top and completely filled to the brim. Tank S is
35 filled with 103551 mℓ of water. The height of the water level in Tank S is 2 cm higher than that in Tank R. Height of Tank S is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 22 cm.
- What is the capacity of Tank S in litres?
- What is the volume of water in the tank now in litres?
(a)
35 of Tank S = 103551 mℓ
15 of Tank S = 103551 ÷ 3 = 34517 mℓ
55 of Tank S = 34517 x 5 = 172585 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank S = 172585 mℓ = 172.585 ℓ
(b)
Fraction of Tank S not filled
= 1 -
35 =
25 Height of Tank S not filled
=
25 x 70 cm
= 28 cm
Height of Tank R
= 70 - 28 - 2
= 40 cm
Volume of remaining water in Tank R
= 40 x 40 x 22
= 35200 cm
3 Volume of remaining water in Tank S
= 70 x 70 x 22
= 107800 cm
3 Total volume of remaining water in the tank
= 35200 + 107800
= 143000 cm
3
1 ℓ = 1000 cm
3 143000 cm
3 = 143 ℓ
Answer(s): (a) 172.585 ℓ; (b) 143 ℓ