The figure, not drawn to scale, is made of two connected cubical tanks, H and J. Tank H is sealed at the top and completely filled to the brim. Tank J is
23 filled with 160818 mℓ of water. The height of the water level in Tank J is 2 cm higher than that in Tank H. Height of Tank J is 69 cm. Water is then drained from the container and the height of the water level from the base falls to 36 cm.
- What is the capacity of Tank J in litres?
- What is the volume of water in the tank now in litres?
(a)
23 of Tank J = 160818 mℓ
13 of Tank J = 160818 ÷ 2 = 80409 mℓ
33 of Tank J = 80409 x 3 = 241227 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank J = 241227 mℓ = 241.227 ℓ
(b)
Fraction of Tank J not filled
= 1 -
23 =
13 Height of Tank J not filled
=
13 x 69 cm
= 23 cm
Height of Tank H
= 69 - 23 - 2
= 44 cm
Volume of remaining water in Tank H
= 44 x 44 x 36
= 69696 cm
3 Volume of remaining water in Tank J
= 69 x 69 x 36
= 171396 cm
3 Total volume of remaining water in the tank
= 69696 + 171396
= 241092 cm
3
1 ℓ = 1000 cm
3 241092 cm
3 = 241.092 ℓ
Answer(s): (a) 241.227 ℓ; (b) 241.092 ℓ