The figure, not drawn to scale, is made of two connected cubical containers, T and U. Container T is sealed at the top and completely filled to the brim. Container U is ²₃ filled with 157486 mℓ of water. The height of the water level in Container U is 5 cm higher than that in Container T. Height of Container U is 69 cm. Water is then drained from the container and the height of the water level from the base falls to 26 cm.

1. What is the capacity of Container U in litres?
2. What is the volume of water in the container now in litres?

(a)
²₃ of Container U = 157486 mℓ
¹₃ of Container U = 157486 ÷ 2 = 78743 mℓ
³₃ of Container U = 78743 x 3 = 236229 mℓ

1 ℓ = 1000 mℓ

Capacity of Container U = 236229 mℓ = 236.229 ℓ

(b)
Fraction of Container U not filled
= 1 - ²₃
= ¹₃

Height of Container U not filled
= ¹₃ x 69 cm
= 23 cm

Height of Container T
= 69 - 23 - 5
= 41 cm

Volume of remaining water in Container T
= 41 x 41 x 26
= 43706 cm³ 

Volume of remaining water in Container U
= 69 x 69 x 26
= 123786 cm³ 

Total volume of remaining water in the container
= 43706 + 123786
= 167492 cm³

1 ℓ = 1000 cm³
167492 cm³ = 167.492 ℓ

Answer(s): (a) 236.229 ℓ; (b) 167.492 ℓ