The figure, not drawn to scale, is made of two connected cubical tanks, R and S. Tank R is sealed at the top and completely filled to the brim. Tank S is
35 filled with 188304 mℓ of water. The height of the water level in Tank S is 4 cm higher than that in Tank R. Height of Tank S is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 31 cm.
- What is the capacity of Tank S in litres?
- What is the volume of water in the tank now in litres?
(a)
35 of Tank S = 188304 mℓ
15 of Tank S = 188304 ÷ 3 = 62768 mℓ
55 of Tank S = 62768 x 5 = 313840 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank S = 313840 mℓ = 313.84 ℓ
(b)
Fraction of Tank S not filled
= 1 -
35 =
25 Height of Tank S not filled
=
25 x 70 cm
= 28 cm
Height of Tank R
= 70 - 28 - 4
= 38 cm
Volume of remaining water in Tank R
= 38 x 38 x 31
= 44764 cm
3 Volume of remaining water in Tank S
= 70 x 70 x 31
= 151900 cm
3 Total volume of remaining water in the tank
= 44764 + 151900
= 196664 cm
3
1 ℓ = 1000 cm
3 196664 cm
3 = 196.664 ℓ
Answer(s): (a) 313.84 ℓ; (b) 196.664 ℓ