The figure, not drawn to scale, is made of two connected cubical tanks, F and G. Tank F is sealed at the top and completely filled to the brim. Tank G is
34 filled with 110409 mℓ of water. The height of the water level in Tank G is 1 cm higher than that in Tank F. Height of Tank G is 56 cm. Water is then drained from the container and the height of the water level from the base falls to 32 cm.
- What is the capacity of Tank G in litres?
- What is the volume of water in the tank now in litres?
(a)
34 of Tank G = 110409 mℓ
14 of Tank G = 110409 ÷ 3 = 36803 mℓ
44 of Tank G = 36803 x 4 = 147212 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank G = 147212 mℓ = 147.212 ℓ
(b)
Fraction of Tank G not filled
= 1 -
34 =
14 Height of Tank G not filled
=
14 x 56 cm
= 14 cm
Height of Tank F
= 56 - 14 - 1
= 41 cm
Volume of remaining water in Tank F
= 41 x 41 x 32
= 53792 cm
3 Volume of remaining water in Tank G
= 56 x 56 x 32
= 100352 cm
3 Total volume of remaining water in the tank
= 53792 + 100352
= 154144 cm
3
1 ℓ = 1000 cm
3 154144 cm
3 = 154.144 ℓ
Answer(s): (a) 147.212 ℓ; (b) 154.144 ℓ