The figure, not drawn to scale, is made of two connected cubical containers, K and L. Container K is sealed at the top and completely filled to the brim. Container L is
35 filled with 153483 mℓ of water. The height of the water level in Container L is 3 cm higher than that in Container K. Height of Container L is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 23 cm.
- What is the capacity of Container L in litres?
- What is the volume of water in the container now in litres?
(a)
35 of Container L = 153483 mℓ
15 of Container L = 153483 ÷ 3 = 51161 mℓ
55 of Container L = 51161 x 5 = 255805 mℓ
1 ℓ = 1000 mℓ
Capacity of Container L = 255805 mℓ = 255.805 ℓ
(b)
Fraction of Container L not filled
= 1 -
35 =
25 Height of Container L not filled
=
25 x 70 cm
= 28 cm
Height of Container K
= 70 - 28 - 3
= 39 cm
Volume of remaining water in Container K
= 39 x 39 x 23
= 34983 cm
3 Volume of remaining water in Container L
= 70 x 70 x 23
= 112700 cm
3 Total volume of remaining water in the container
= 34983 + 112700
= 147683 cm
3
1 ℓ = 1000 cm
3 147683 cm
3 = 147.683 ℓ
Answer(s): (a) 255.805 ℓ; (b) 147.683 ℓ