The figure, not drawn to scale, is made of two connected cubical tanks, L and M. Tank L is sealed at the top and completely filled to the brim. Tank M is
35 filled with 117021 mℓ of water. The height of the water level in Tank M is 2 cm higher than that in Tank L. Height of Tank M is 60 cm. Water is then drained from the container and the height of the water level from the base falls to 34 cm.
- What is the capacity of Tank M in litres?
- What is the volume of water in the tank now in litres?
(a)
35 of Tank M = 117021 mℓ
15 of Tank M = 117021 ÷ 3 = 39007 mℓ
55 of Tank M = 39007 x 5 = 195035 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank M = 195035 mℓ = 195.035 ℓ
(b)
Fraction of Tank M not filled
= 1 -
35 =
25 Height of Tank M not filled
=
25 x 60 cm
= 24 cm
Height of Tank L
= 60 - 24 - 2
= 34 cm
Volume of remaining water in Tank L
= 34 x 34 x 34
= 39304 cm
3 Volume of remaining water in Tank M
= 60 x 60 x 34
= 122400 cm
3 Total volume of remaining water in the tank
= 39304 + 122400
= 161704 cm
3
1 ℓ = 1000 cm
3 161704 cm
3 = 161.704 ℓ
Answer(s): (a) 195.035 ℓ; (b) 161.704 ℓ