The figure, not drawn to scale, is made of two connected cubical tanks, G and H. Tank G is sealed at the top and completely filled to the brim. Tank H is
35 filled with 117321 mℓ of water. The height of the water level in Tank H is 4 cm higher than that in Tank G. Height of Tank H is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 39 cm.
- What is the capacity of Tank H in litres?
- What is the volume of water in the tank now in litres?
(a)
35 of Tank H = 117321 mℓ
15 of Tank H = 117321 ÷ 3 = 39107 mℓ
55 of Tank H = 39107 x 5 = 195535 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank H = 195535 mℓ = 195.535 ℓ
(b)
Fraction of Tank H not filled
= 1 -
35 =
25 Height of Tank H not filled
=
25 x 70 cm
= 28 cm
Height of Tank G
= 70 - 28 - 4
= 38 cm
Volume of remaining water in Tank G
= 38 x 38 x 39
= 56316 cm
3 Volume of remaining water in Tank H
= 70 x 70 x 39
= 191100 cm
3 Total volume of remaining water in the tank
= 56316 + 191100
= 247416 cm
3
1 ℓ = 1000 cm
3 247416 cm
3 = 247.416 ℓ
Answer(s): (a) 195.535 ℓ; (b) 247.416 ℓ