The figure, not drawn to scale, is made of two connected cubical tanks, F and G. Tank F is sealed at the top and completely filled to the brim. Tank G is
45 filled with 152524 mℓ of water. The height of the water level in Tank G is 3 cm higher than that in Tank F. Height of Tank G is 60 cm. Water is then drained from the container and the height of the water level from the base falls to 39 cm.
- What is the capacity of Tank G in litres?
- What is the volume of water in the tank now in litres?
(a)
45 of Tank G = 152524 mℓ
15 of Tank G = 152524 ÷ 4 = 38131 mℓ
55 of Tank G = 38131 x 5 = 190655 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank G = 190655 mℓ = 190.655 ℓ
(b)
Fraction of Tank G not filled
= 1 -
45 =
15 Height of Tank G not filled
=
15 x 60 cm
= 12 cm
Height of Tank F
= 60 - 12 - 3
= 45 cm
Volume of remaining water in Tank F
= 45 x 45 x 39
= 78975 cm
3 Volume of remaining water in Tank G
= 60 x 60 x 39
= 140400 cm
3 Total volume of remaining water in the tank
= 78975 + 140400
= 219375 cm
3
1 ℓ = 1000 cm
3 219375 cm
3 = 219.375 ℓ
Answer(s): (a) 190.655 ℓ; (b) 219.375 ℓ