The figure, not drawn to scale, is made of two connected cubical tanks, W and X. Tank W is sealed at the top and completely filled to the brim. Tank X is
34 filled with 140505 mℓ of water. The height of the water level in Tank X is 5 cm higher than that in Tank W. Height of Tank X is 62 cm. Water is then drained from the container and the height of the water level from the base falls to 20 cm.
- What is the capacity of Tank X in litres?
- What is the volume of water in the tank now in litres?
(a)
34 of Tank X = 140505 mℓ
14 of Tank X = 140505 ÷ 3 = 46835 mℓ
44 of Tank X = 46835 x 4 = 187340 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank X = 187340 mℓ = 187.34 ℓ
(b)
Fraction of Tank X not filled
= 1 -
34 =
14 Height of Tank X not filled
=
14 x 62 cm
= 15.5 cm
Height of Tank W
= 62 - 15.5 - 5
= 41.5 cm
Volume of remaining water in Tank W
= 41.5 x 41.5 x 20
= 34445 cm
3 Volume of remaining water in Tank X
= 62 x 62 x 20
= 76880 cm
3 Total volume of remaining water in the tank
= 34445 + 76880
= 111325 cm
3
1 ℓ = 1000 cm
3 111325 cm
3 = 111.325 ℓ
Answer(s): (a) 187.34 ℓ; (b) 111.325 ℓ