The figure, not drawn to scale, is made of two connected cubical containers, S and T. Container S is sealed at the top and completely filled to the brim. Container T is ³₄ filled with 176586 mℓ of water. The height of the water level in Container T is 2 cm higher than that in Container S. Height of Container T is 68 cm. Water is then drained from the container and the height of the water level from the base falls to 31 cm.

1. What is the capacity of Container T in litres?
2. What is the volume of water in the container now in litres?

(a)
³₄ of Container T = 176586 mℓ
¹₄ of Container T = 176586 ÷ 3 = 58862 mℓ
⁴₄ of Container T = 58862 x 4 = 235448 mℓ

1 ℓ = 1000 mℓ

Capacity of Container T = 235448 mℓ = 235.448 ℓ

(b)
Fraction of Container T not filled
= 1 - ³₄
= ¹₄

Height of Container T not filled
= ¹₄ x 68 cm
= 17 cm

Height of Container S
= 68 - 17 - 2
= 49 cm

Volume of remaining water in Container S
= 49 x 49 x 31
= 74431 cm³ 

Volume of remaining water in Container T
= 68 x 68 x 31
= 143344 cm³ 

Total volume of remaining water in the container
= 74431 + 143344
= 217775 cm³

1 ℓ = 1000 cm³
217775 cm³ = 217.775 ℓ

Answer(s): (a) 235.448 ℓ; (b) 217.775 ℓ