The figure, not drawn to scale, is made of two connected cubical tanks, D and E. Tank D is sealed at the top and completely filled to the brim. Tank E is
45 filled with 134980 mℓ of water. The height of the water level in Tank E is 3 cm higher than that in Tank D. Height of Tank E is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 25 cm.
- What is the capacity of Tank E in litres?
- What is the volume of water in the tank now in litres?
(a)
45 of Tank E = 134980 mℓ
15 of Tank E = 134980 ÷ 4 = 33745 mℓ
55 of Tank E = 33745 x 5 = 168725 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank E = 168725 mℓ = 168.725 ℓ
(b)
Fraction of Tank E not filled
= 1 -
45 =
15 Height of Tank E not filled
=
15 x 70 cm
= 14 cm
Height of Tank D
= 70 - 14 - 3
= 53 cm
Volume of remaining water in Tank D
= 53 x 53 x 25
= 70225 cm
3 Volume of remaining water in Tank E
= 70 x 70 x 25
= 122500 cm
3 Total volume of remaining water in the tank
= 70225 + 122500
= 192725 cm
3
1 ℓ = 1000 cm
3 192725 cm
3 = 192.725 ℓ
Answer(s): (a) 168.725 ℓ; (b) 192.725 ℓ