The figure, not drawn to scale, is made of two connected cubical containers, A and B. Container A is sealed at the top and completely filled to the brim. Container B is ³₄ filled with 107706 mℓ of water. The height of the water level in Container B is 5 cm higher than that in Container A. Height of Container B is 66 cm. Water is then drained from the container and the height of the water level from the base falls to 20 cm.

1. What is the capacity of Container B in litres?
2. What is the volume of water in the container now in litres?

(a)
³₄ of Container B = 107706 mℓ
¹₄ of Container B = 107706 ÷ 3 = 35902 mℓ
⁴₄ of Container B = 35902 x 4 = 143608 mℓ

1 ℓ = 1000 mℓ

Capacity of Container B = 143608 mℓ = 143.608 ℓ

(b)
Fraction of Container B not filled
= 1 - ³₄
= ¹₄

Height of Container B not filled
= ¹₄ x 66 cm
= 16.5 cm

Height of Container A
= 66 - 16.5 - 5
= 44.5 cm

Volume of remaining water in Container A
= 44.5 x 44.5 x 20
= 39605 cm³ 

Volume of remaining water in Container B
= 66 x 66 x 20
= 87120 cm³ 

Total volume of remaining water in the container
= 39605 + 87120
= 126725 cm³

1 ℓ = 1000 cm³
126725 cm³ = 126.725 ℓ

Answer(s): (a) 143.608 ℓ; (b) 126.725 ℓ