The figure, not drawn to scale, is made of two connected cubical tanks, F and G. Tank F is sealed at the top and completely filled to the brim. Tank G is
34 filled with 153399 mℓ of water. The height of the water level in Tank G is 4 cm higher than that in Tank F. Height of Tank G is 68 cm. Water is then drained from the container and the height of the water level from the base falls to 39 cm.
- What is the capacity of Tank G in litres?
- What is the volume of water in the tank now in litres?
(a)
34 of Tank G = 153399 mℓ
14 of Tank G = 153399 ÷ 3 = 51133 mℓ
44 of Tank G = 51133 x 4 = 204532 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank G = 204532 mℓ = 204.532 ℓ
(b)
Fraction of Tank G not filled
= 1 -
34 =
14 Height of Tank G not filled
=
14 x 68 cm
= 17 cm
Height of Tank F
= 68 - 17 - 4
= 47 cm
Volume of remaining water in Tank F
= 47 x 47 x 39
= 86151 cm
3 Volume of remaining water in Tank G
= 68 x 68 x 39
= 180336 cm
3 Total volume of remaining water in the tank
= 86151 + 180336
= 266487 cm
3
1 ℓ = 1000 cm
3 266487 cm
3 = 266.487 ℓ
Answer(s): (a) 204.532 ℓ; (b) 266.487 ℓ