The figure, not drawn to scale, is made of two connected cubical tanks, B and C. Tank B is sealed at the top and completely filled to the brim. Tank C is
23 filled with 194132 mℓ of water. The height of the water level in Tank C is 2 cm higher than that in Tank B. Height of Tank C is 69 cm. Water is then drained from the container and the height of the water level from the base falls to 32 cm.
- What is the capacity of Tank C in litres?
- What is the volume of water in the tank now in litres?
(a)
23 of Tank C = 194132 mℓ
13 of Tank C = 194132 ÷ 2 = 97066 mℓ
33 of Tank C = 97066 x 3 = 291198 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank C = 291198 mℓ = 291.198 ℓ
(b)
Fraction of Tank C not filled
= 1 -
23 =
13 Height of Tank C not filled
=
13 x 69 cm
= 23 cm
Height of Tank B
= 69 - 23 - 2
= 44 cm
Volume of remaining water in Tank B
= 44 x 44 x 32
= 61952 cm
3 Volume of remaining water in Tank C
= 69 x 69 x 32
= 152352 cm
3 Total volume of remaining water in the tank
= 61952 + 152352
= 214304 cm
3
1 ℓ = 1000 cm
3 214304 cm
3 = 214.304 ℓ
Answer(s): (a) 291.198 ℓ; (b) 214.304 ℓ