The figure, not drawn to scale, is made of two connected cubical containers, P and Q. Container P is sealed at the top and completely filled to the brim. Container Q is
23 filled with 134158 mℓ of water. The height of the water level in Container Q is 2 cm higher than that in Container P. Height of Container Q is 66 cm. Water is then drained from the container and the height of the water level from the base falls to 28 cm.
- What is the capacity of Container Q in litres?
- What is the volume of water in the container now in litres?
(a)
23 of Container Q = 134158 mℓ
13 of Container Q = 134158 ÷ 2 = 67079 mℓ
33 of Container Q = 67079 x 3 = 201237 mℓ
1 ℓ = 1000 mℓ
Capacity of Container Q = 201237 mℓ = 201.237 ℓ
(b)
Fraction of Container Q not filled
= 1 -
23 =
13 Height of Container Q not filled
=
13 x 66 cm
= 22 cm
Height of Container P
= 66 - 22 - 2
= 42 cm
Volume of remaining water in Container P
= 42 x 42 x 28
= 49392 cm
3 Volume of remaining water in Container Q
= 66 x 66 x 28
= 121968 cm
3 Total volume of remaining water in the container
= 49392 + 121968
= 171360 cm
3
1 ℓ = 1000 cm
3 171360 cm
3 = 171.36 ℓ
Answer(s): (a) 201.237 ℓ; (b) 171.36 ℓ