The figure, not drawn to scale, is made of two connected cubical containers, B and C. Container B is sealed at the top and completely filled to the brim. Container C is ³₄ filled with 123960 mℓ of water. The height of the water level in Container C is 1 cm higher than that in Container B. Height of Container C is 57 cm. Water is then drained from the container and the height of the water level from the base falls to 32 cm.

1. What is the capacity of Container C in litres?
2. What is the volume of water in the container now in litres?

(a)
³₄ of Container C = 123960 mℓ
¹₄ of Container C = 123960 ÷ 3 = 41320 mℓ
⁴₄ of Container C = 41320 x 4 = 165280 mℓ

1 ℓ = 1000 mℓ

Capacity of Container C = 165280 mℓ = 165.28 ℓ

(b)
Fraction of Container C not filled
= 1 - ³₄
= ¹₄

Height of Container C not filled
= ¹₄ x 57 cm
= 14.25 cm

Height of Container B
= 57 - 14.25 - 1
= 41.75 cm

Volume of remaining water in Container B
= 41.75 x 41.75 x 32
= 55778 cm³ 

Volume of remaining water in Container C
= 57 x 57 x 32
= 103968 cm³ 

Total volume of remaining water in the container
= 55778 + 103968
= 159746 cm³

1 ℓ = 1000 cm³
159746 cm³ = 159.746 ℓ

Answer(s): (a) 165.28 ℓ; (b) 159.746 ℓ