The figure, not drawn to scale, is made of two connected cubical containers, N and P. Container N is sealed at the top and completely filled to the brim. Container P is
45 filled with 173844 mℓ of water. The height of the water level in Container P is 4 cm higher than that in Container N. Height of Container P is 65 cm. Water is then drained from the container and the height of the water level from the base falls to 28 cm.
- What is the capacity of Container P in litres?
- What is the volume of water in the container now in litres?
(a)
45 of Container P = 173844 mℓ
15 of Container P = 173844 ÷ 4 = 43461 mℓ
55 of Container P = 43461 x 5 = 217305 mℓ
1 ℓ = 1000 mℓ
Capacity of Container P = 217305 mℓ = 217.305 ℓ
(b)
Fraction of Container P not filled
= 1 -
45 =
15 Height of Container P not filled
=
15 x 65 cm
= 13 cm
Height of Container N
= 65 - 13 - 4
= 48 cm
Volume of remaining water in Container N
= 48 x 48 x 28
= 64512 cm
3 Volume of remaining water in Container P
= 65 x 65 x 28
= 118300 cm
3 Total volume of remaining water in the container
= 64512 + 118300
= 182812 cm
3
1 ℓ = 1000 cm
3 182812 cm
3 = 182.812 ℓ
Answer(s): (a) 217.305 ℓ; (b) 182.812 ℓ