The figure, not drawn to scale, is made of two connected cubical tanks, B and C. Tank B is sealed at the top and completely filled to the brim. Tank C is
35 filled with 161328 mℓ of water. The height of the water level in Tank C is 2 cm higher than that in Tank B. Height of Tank C is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 22 cm.
- What is the capacity of Tank C in litres?
- What is the volume of water in the tank now in litres?
(a)
35 of Tank C = 161328 mℓ
15 of Tank C = 161328 ÷ 3 = 53776 mℓ
55 of Tank C = 53776 x 5 = 268880 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank C = 268880 mℓ = 268.88 ℓ
(b)
Fraction of Tank C not filled
= 1 -
35 =
25 Height of Tank C not filled
=
25 x 70 cm
= 28 cm
Height of Tank B
= 70 - 28 - 2
= 40 cm
Volume of remaining water in Tank B
= 40 x 40 x 22
= 35200 cm
3 Volume of remaining water in Tank C
= 70 x 70 x 22
= 107800 cm
3 Total volume of remaining water in the tank
= 35200 + 107800
= 143000 cm
3
1 ℓ = 1000 cm
3 143000 cm
3 = 143 ℓ
Answer(s): (a) 268.88 ℓ; (b) 143 ℓ