The figure, not drawn to scale, is made of two connected cubical containers, H and J. Container H is sealed at the top and completely filled to the brim. Container J is ²₅ filled with 108382 mℓ of water. The height of the water level in Container J is 4 cm higher than that in Container H. Height of Container J is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 28 cm.

1. What is the capacity of Container J in litres?
2. What is the volume of water in the container now in litres?

(a)
²₅ of Container J = 108382 mℓ
¹₅ of Container J = 108382 ÷ 2 = 54191 mℓ
⁵₅ of Container J = 54191 x 5 = 270955 mℓ

1 ℓ = 1000 mℓ

Capacity of Container J = 270955 mℓ = 270.955 ℓ

(b)
Fraction of Container J not filled
= 1 - ²₅
= ³₅

Height of Container J not filled
= ³₅ x 70 cm
= 42 cm

Height of Container H
= 70 - 42 - 4
= 24 cm

Volume of remaining water in Container H
= 24 x 24 x 28
= 16128 cm³ 

Volume of remaining water in Container J
= 70 x 70 x 28
= 137200 cm³ 

Total volume of remaining water in the container
= 16128 + 137200
= 153328 cm³

1 ℓ = 1000 cm³
153328 cm³ = 153.328 ℓ

Answer(s): (a) 270.955 ℓ; (b) 153.328 ℓ