The figure is not drawn to scale. Tank J and Tank K have base areas of 4000 cm
2 and 2500 cm
2 respectively. Water was poured into an empty rectangular Tank J until it reached a height of 46 cm. Some of the water was then poured from Tank J into Tank K which contained 1.9 ℓ of water until the height of the water in both tanks were the same.
- Find the new height of the water in Tank J.
- How many litres of water were poured into Tank K?
(a)
Volume of water in Tank J
= 4000 x 46
= 184000 cm
3 (Base area x height)
1 ℓ = 1000 cm
3 1.9 ℓ = 1900 cm
3 Total volume of Tank J and Tank K
= 184000 + 1900
= 185900 cm
3 Total base area of Tank J and Tank K
= 4000 + 2500
= 6500 cm²
Height of Tank J after
= 185900 ÷ 6500
= 28.6 cm
(b)
Volume of water in Tank K after pouring
= 2500 x 28.6
= 71500 cm
3 Volume of water poured into Tank K
= 71500 - 2500
= 69000 cm
3 69000 mℓ = 69 ℓ
Answer(s): (a) 28.6 cm; (b) 69 ℓ