The figure is not drawn to scale. Container D and Container E have base areas of 4000 cm
2 and 1500 cm
2 respectively. Water was poured into an empty rectangular Container D until it reached a height of 42 cm. Some of the water was then poured from Container D into Container E which contained 2.5 ℓ of water until the height of the water in both containers were the same.
- Find the new height of the water in Container D.
- How many litres of water were poured into Container E?
(a)
Volume of water in Container D
= 4000 x 42
= 168000 cm
3 (Base area x height)
1 ℓ = 1000 cm
3 2.5 ℓ = 2500 cm
3 Total volume of Container D and Container E
= 168000 + 2500
= 170500 cm
3 Total base area of Container D and Container E
= 4000 + 1500
= 5500 cm²
Height of Container D after
= 170500 ÷ 5500
= 31 cm
(b)
Volume of water in Container E after pouring
= 1500 x 31
= 46500 cm
3 Volume of water poured into Container E
= 46500 - 1500
= 45000 cm
3 45000 mℓ = 45 ℓ
Answer(s): (a) 31 cm; (b) 45 ℓ