The figure is not drawn to scale. Tank T and Tank U have base areas of 3000 cm
2 and 2500 cm
2 respectively. Water was poured into an empty rectangular Tank T until it reached a height of 29 cm. Some of the water was then poured from Tank T into Tank U which contained 2.1 ℓ of water until the height of the water in both tanks were the same.
- Find the new height of the water in Tank T.
- How many litres of water were poured into Tank U?
(a)
Volume of water in Tank T
= 3000 x 29
= 87000 cm
3 (Base area x height)
1 ℓ = 1000 cm
3 2.1 ℓ = 2100 cm
3 Total volume of Tank T and Tank U
= 87000 + 2100
= 89100 cm
3 Total base area of Tank T and Tank U
= 3000 + 2500
= 5500 cm²
Height of Tank T after
= 89100 ÷ 5500
= 16.2 cm
(b)
Volume of water in Tank U after pouring
= 2500 x 16.2
= 40500 cm
3 Volume of water poured into Tank U
= 40500 - 2500
= 38000 cm
3 38000 mℓ = 38 ℓ
Answer(s): (a) 16.2 cm; (b) 38 ℓ