The figure is not drawn to scale. Tank Y and Tank Z have base areas of 3500 cm
2 and 3000 cm
2 respectively. Water was poured into an empty rectangular Tank Y until it reached a height of 46 cm. Some of the water was then poured from Tank Y into Tank Z which contained 1.5 ℓ of water until the height of the water in both tanks were the same.
- Find the new height of the water in Tank Y.
- How many litres of water were poured into Tank Z?
(a)
Volume of water in Tank Y
= 3500 x 46
= 161000 cm
3 (Base area x height)
1 ℓ = 1000 cm
3 1.5 ℓ = 1500 cm
3 Total volume of Tank Y and Tank Z
= 161000 + 1500
= 162500 cm
3 Total base area of Tank Y and Tank Z
= 3500 + 3000
= 6500 cm²
Height of Tank Y after
= 162500 ÷ 6500
= 25 cm
(b)
Volume of water in Tank Z after pouring
= 3000 x 25
= 75000 cm
3 Volume of water poured into Tank Z
= 75000 - 3000
= 72000 cm
3 72000 mℓ = 72 ℓ
Answer(s): (a) 25 cm; (b) 72 ℓ