The figure is not drawn to scale. Container Z and Container A have base areas of 2500 cm
2 and 1000 cm
2 respectively. Water was poured into an empty rectangular Container Z until it reached a height of 26 cm. Some of the water was then poured from Container Z into Container A which contained 1.5 ℓ of water until the height of the water in both containers were the same.
- Find the new height of the water in Container Z.
- How many litres of water were poured into Container A?
(a)
Volume of water in Container Z
= 2500 x 26
= 65000 cm
3 (Base area x height)
1 ℓ = 1000 cm
3 1.5 ℓ = 1500 cm
3 Total volume of Container Z and Container A
= 65000 + 1500
= 66500 cm
3 Total base area of Container Z and Container A
= 2500 + 1000
= 3500 cm²
Height of Container Z after
= 66500 ÷ 3500
= 19 cm
(b)
Volume of water in Container A after pouring
= 1000 x 19
= 19000 cm
3 Volume of water poured into Container A
= 19000 - 1000
= 18000 cm
3 18000 mℓ = 18 ℓ
Answer(s): (a) 19 cm; (b) 18 ℓ