The figure is not drawn to scale. Container J and Container K have base areas of 3000 cm
2 and 2500 cm
2 respectively. Water was poured into an empty rectangular Container J until it reached a height of 43 cm. Some of the water was then poured from Container J into Container K which contained 1.9 ℓ of water until the height of the water in both containers were the same.
- Find the new height of the water in Container J.
- How many litres of water were poured into Container K?
(a)
Volume of water in Container J
= 3000 x 43
= 129000 cm
3 (Base area x height)
1 ℓ = 1000 cm
3 1.9 ℓ = 1900 cm
3 Total volume of Container J and Container K
= 129000 + 1900
= 130900 cm
3 Total base area of Container J and Container K
= 3000 + 2500
= 5500 cm²
Height of Container J after
= 130900 ÷ 5500
= 23.8 cm
(b)
Volume of water in Container K after pouring
= 2500 x 23.8
= 59500 cm
3 Volume of water poured into Container K
= 59500 - 2500
= 57000 cm
3 57000 mℓ = 57 ℓ
Answer(s): (a) 23.8 cm; (b) 57 ℓ