The figure is not drawn to scale. Container C and Container D have base areas of 1500 cm
2 and 1000 cm
2 respectively. Water was poured into an empty rectangular Container C until it reached a height of 23 cm. Some of the water was then poured from Container C into Container D which contained 1.5 ℓ of water until the height of the water in both containers were the same.
- Find the new height of the water in Container C.
- How many litres of water were poured into Container D?
(a)
Volume of water in Container C
= 1500 x 23
= 34500 cm
3 (Base area x height)
1 ℓ = 1000 cm
3 1.5 ℓ = 1500 cm
3 Total volume of Container C and Container D
= 34500 + 1500
= 36000 cm
3 Total base area of Container C and Container D
= 1500 + 1000
= 2500 cm²
Height of Container C after
= 36000 ÷ 2500
= 14.4 cm
(b)
Volume of water in Container D after pouring
= 1000 x 14.4
= 14400 cm
3 Volume of water poured into Container D
= 14400 - 1000
= 13400 cm
3 13400 mℓ = 13.4 ℓ
Answer(s): (a) 14.4 cm; (b) 13.4 ℓ