The figure is not drawn to scale. Container E and Container F have base areas of 3000 cm
2 and 2500 cm
2 respectively. Water was poured into an empty rectangular Container E until it reached a height of 30 cm. Some of the water was then poured from Container E into Container F which contained 1.3 ℓ of water until the height of the water in both containers were the same.
- Find the new height of the water in Container E.
- How many litres of water were poured into Container F?
(a)
Volume of water in Container E
= 3000 x 30
= 90000 cm
3 (Base area x height)
1 ℓ = 1000 cm
3 1.3 ℓ = 1300 cm
3 Total volume of Container E and Container F
= 90000 + 1300
= 91300 cm
3 Total base area of Container E and Container F
= 3000 + 2500
= 5500 cm²
Height of Container E after
= 91300 ÷ 5500
= 16.6 cm
(b)
Volume of water in Container F after pouring
= 2500 x 16.6
= 41500 cm
3 Volume of water poured into Container F
= 41500 - 2500
= 39000 cm
3 39000 mℓ = 39 ℓ
Answer(s): (a) 16.6 cm; (b) 39 ℓ