The figure is not drawn to scale. Container K and Container L have base areas of 2500 cm
2 and 2000 cm
2 respectively. Water was poured into an empty rectangular Container K until it reached a height of 39 cm. Some of the water was then poured from Container K into Container L which contained 1.5 ℓ of water until the height of the water in both containers were the same.
- Find the new height of the water in Container K.
- How many litres of water were poured into Container L?
(a)
Volume of water in Container K
= 2500 x 39
= 97500 cm
3 (Base area x height)
1 ℓ = 1000 cm
3 1.5 ℓ = 1500 cm
3 Total volume of Container K and Container L
= 97500 + 1500
= 99000 cm
3 Total base area of Container K and Container L
= 2500 + 2000
= 4500 cm²
Height of Container K after
= 99000 ÷ 4500
= 22 cm
(b)
Volume of water in Container L after pouring
= 2000 x 22
= 44000 cm
3 Volume of water poured into Container L
= 44000 - 2000
= 42000 cm
3 42000 mℓ = 42 ℓ
Answer(s): (a) 22 cm; (b) 42 ℓ