The figure is not drawn to scale. Tank L and Tank M have base areas of 2500 cm
2 and 1500 cm
2 respectively. Water was poured into an empty rectangular Tank L until it reached a height of 25 cm. Some of the water was then poured from Tank L into Tank M which contained 1.5 ℓ of water until the height of the water in both tanks were the same.
- Find the new height of the water in Tank L.
- How many litres of water were poured into Tank M?
(a)
Volume of water in Tank L
= 2500 x 25
= 62500 cm
3 (Base area x height)
1 ℓ = 1000 cm
3 1.5 ℓ = 1500 cm
3 Total volume of Tank L and Tank M
= 62500 + 1500
= 64000 cm
3 Total base area of Tank L and Tank M
= 2500 + 1500
= 4000 cm²
Height of Tank L after
= 64000 ÷ 4000
= 16 cm
(b)
Volume of water in Tank M after pouring
= 1500 x 16
= 24000 cm
3 Volume of water poured into Tank M
= 24000 - 1500
= 22500 cm
3 22500 mℓ = 22.5 ℓ
Answer(s): (a) 16 cm; (b) 22.5 ℓ