The figure shows 2 containers, Container U and Container V. Container V is completely empty while Container U is filled with water to the brim. Water from Tap T flows in at a rate of 4.8 litres per minute while water drains from Tap S at a rate of 1.44 litres per minute. Both taps are turned on at the same time. After some time, the heights of the water level in both tanks became the same.
- Find the time taken for the heights of the water level to be the same in both tanks.
- Find the height of the water level at that point of time.
(a)
Base area of Container U
= 40 x 15
= 600 cm
2 1 ℓ = 1000 cm
3 4.8 ℓ = 4800 cm
3 1.44 ℓ = 1440 cm
3 Height increase per minute for Container U
= 4800 ÷ 600
= 8 cm/min
Base area of Container V
= 40 x 18
= 720 cm
2 Height decrease per minute for Container V
= 1440 ÷ 720
= 2 cm/min
Let t be the time taken for both the water levels to become the same.
8 t = 12 - 2 t
10 t = 12
1 t = 1.2 min
(b)
Height of the water level
= 8 t
= 8 x 1.2
= 9.6 cm
Answer(s): (a) 1.2 min; (b) 9.6 cm