The figure shows 2 containers, Container S and Container T. Container T is completely empty while Container S is filled with water to the brim. Water from Tap R flows in at a rate of 2.4 litres per minute while water drains from Tap Q at a rate of 0.72 litres per minute. Both taps are turned on at the same time. After some time, the heights of the water level in both tanks became the same.
- Find the time taken for the heights of the water level to be the same in both tanks.
- Find the height of the water level at that point of time.
(a)
Base area of Container S
= 30 x 25
= 750 cm
2 1 ℓ = 1000 cm
3 2.4 ℓ = 2400 cm
3 0.72 ℓ = 720 cm
3 Height increase per minute for Container S
= 2400 ÷ 750
= 3.2 cm/min
Base area of Container T
= 20 x 20
= 400 cm
2 Height decrease per minute for Container T
= 720 ÷ 400
= 1.8 cm/min
Let t be the time taken for both the water levels to become the same.
3.2 t = 16 - 1.8 t
5 t = 16
1 t = 3.2 min
(b)
Height of the water level
= 3.2 t
= 3.2 x 3.2
= 10.24 cm
Answer(s): (a) 3.2 min; (b) 10.24 cm