A rectangular container, 90 cm by 50 cm by 50 cm, is filled with water to a height of 9 cm. The ratio of the volume of water in the container to that in a pail is 5 : 2. If
67 of the pail is filled with water, find
- the volume of the pail.
- the minimum number of such pails to fill the container.
(a)
Volume of water in the container
= 90 x 50 x 9
= 40500 cm
3 5 u = 40500 cm
3 1 u = 40500 ÷ 5 = 8100 cm
3 2 u = 2 x 8100 = 16200 cm
3 Volume of water in
67 of the pail = 16200 cm
3 Volume of the pail
= 16200 ÷
67 = 16200 x
76 = 18900 cm
3 (b)
Volume of the container
= 90 x 50 x 50
= 225000 cm
3 Number of pails to fill the container
= 225000 ÷ 18900
= 11 r 17100
Minimum number of pails to fill the container
= 11 + 1
= 12
Answer(s): (a) 18900 cm
3; (b) 12