A rectangular container, 90 cm by 40 cm by 40 cm, is filled with water to a height of 10 cm. The ratio of the volume of water in the container to that in a pail is 9 : 4. If
57 of the pail is filled with water, find
- the volume of the pail.
- the minimum number of such pails to fill the container.
(a)
Volume of water in the container
= 90 x 40 x 10
= 36000 cm
3 9 u = 36000 cm
3 1 u = 36000 ÷ 9 = 4000 cm
3 4 u = 4 x 4000 = 16000 cm
3 Volume of water in
57 of the pail = 16000 cm
3 Volume of the pail
= 16000 ÷
57 = 16000 x
75 = 22400 cm
3 (b)
Volume of the container
= 90 x 40 x 40
= 144000 cm
3 Number of pails to fill the container
= 144000 ÷ 22400
= 6 r 9600
Minimum number of pails to fill the container
= 6 + 1
= 7
Answer(s): (a) 22400 cm
3; (b) 7