A rectangular container, 80 cm by 45 cm by 40 cm, is filled with water to a height of 11 cm. The ratio of the volume of water in the container to that in a barrel is 11 : 2. If
57 of the barrel is filled with water, find
- the volume of the barrel.
- the minimum number of such barrels to fill the container.
(a)
Volume of water in the container
= 80 x 45 x 11
= 39600 cm
3 11 u = 39600 cm
3 1 u = 39600 ÷ 11 = 3600 cm
3 2 u = 2 x 3600 = 7200 cm
3 Volume of water in
57 of the barrel = 7200 cm
3 Volume of the barrel
= 7200 ÷
57 = 7200 x
75 = 10080 cm
3 (b)
Volume of the container
= 80 x 45 x 40
= 144000 cm
3 Number of barrels to fill the container
= 144000 ÷ 10080
= 14 r 2880
Minimum number of barrels to fill the container
= 14 + 1
= 15
Answer(s): (a) 10080 cm
3; (b) 15