An equilateral triangle, NPQ, is folded as shown in the figure. Find
- ∠DCQ
- ∠PDQ.
(a)
∠CQD = 60° (Equilateral triangle NPQ)
∠DCQ
= 180° - 60° - 54° (Angles sum of triangle)
= 66°
(b)
∠PDQ
= 180° - 54° - 54°
= 72° (Angles on a straight line)
Answer(s): (a) 66°; (b) 72°