An equilateral triangle, ZAB, is folded as shown in the figure. Find
- ∠DCB
- ∠ADB.
(a)
∠CBD = 60° (Equilateral triangle ZAB)
∠DCB
= 180° - 60° - 54° (Angles sum of triangle)
= 66°
(b)
∠ADB
= 180° - 54° - 54°
= 72° (Angles on a straight line)
Answer(s): (a) 66°; (b) 72°