An equilateral triangle, NPQ, is folded as shown in the figure. Find
- ∠DCQ
- ∠PDQ.
(a)
∠CQD = 60° (Equilateral triangle NPQ)
∠DCQ
= 180° - 60° - 53° (Angles sum of triangle)
= 67°
(b)
∠PDQ
= 180° - 53° - 53°
= 74° (Angles on a straight line)
Answer(s): (a) 67°; (b) 74°