An equilateral triangle, XYZ, is folded as shown in the figure. Find
- ∠JHZ
- ∠YJZ.
(a)
∠HZJ = 60° (Equilateral triangle XYZ)
∠JHZ
= 180° - 60° - 56° (Angles sum of triangle)
= 64°
(b)
∠YJZ
= 180° - 56° - 56°
= 68° (Angles on a straight line)
Answer(s): (a) 64°; (b) 68°