An equilateral triangle, JKL, is folded as shown in the figure. Find
- ∠DCL
- ∠KDL.
(a)
∠CLD = 60° (Equilateral triangle JKL)
∠DCL
= 180° - 60° - 57° (Angles sum of triangle)
= 63°
(b)
∠KDL
= 180° - 57° - 57°
= 66° (Angles on a straight line)
Answer(s): (a) 63°; (b) 66°