An equilateral triangle, CDE, is folded as shown in the figure. Find
- ∠RQE
- ∠DRE.
(a)
∠QER = 60° (Equilateral triangle CDE)
∠RQE
= 180° - 60° - 55° (Angles sum of triangle)
= 65°
(b)
∠DRE
= 180° - 55° - 55°
= 70° (Angles on a straight line)
Answer(s): (a) 65°; (b) 70°