An equilateral triangle, ABC, is folded as shown in the figure. Find
- ∠JHC
- ∠BJC.
(a)
∠HCJ = 60° (Equilateral triangle ABC)
∠JHC
= 180° - 60° - 53° (Angles sum of triangle)
= 67°
(b)
∠BJC
= 180° - 53° - 53°
= 74° (Angles on a straight line)
Answer(s): (a) 67°; (b) 74°