An equilateral triangle, NPQ, is folded as shown in the figure. Find
- ∠AZQ
- ∠PAQ.
(a)
∠ZQA = 60° (Equilateral triangle NPQ)
∠AZQ
= 180° - 60° - 57° (Angles sum of triangle)
= 63°
(b)
∠PAQ
= 180° - 57° - 57°
= 66° (Angles on a straight line)
Answer(s): (a) 63°; (b) 66°