An equilateral triangle, CDE, is folded as shown in the figure. Find
- ∠NME
- ∠DNE.
(a)
∠MEN = 60° (Equilateral triangle CDE)
∠NME
= 180° - 60° - 58° (Angles sum of triangle)
= 62°
(b)
∠DNE
= 180° - 58° - 58°
= 64° (Angles on a straight line)
Answer(s): (a) 62°; (b) 64°